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Q31E
Expert-verifiedTwo large tanks, each holding 100 L of liquid, are interconnected by pipes, with the liquid flowing from tank A into tank B at a rate of 3 L/min and from B into A at a rate of 1 L/min (see Figure 5.2). The liquid inside each tank is kept well stirred. A brine solution with a concentration of 0.2 kg/L of salt flows into tank A at a rate of 6 L/min. The (diluted) solution flows out of the system from tank A at 4 L/min and from tank B at 2 L/min. If, initially, tank A contains pure water and tank B contains 20 kg of salt, determine the mass of salt in each tank at a time .
The mass of salt in each tank at the time is;
and
.
Elimination Procedure for 2 × 2 Systems:
To find a general solution for the system
Where and are polynomials in
Vieta’s formulas for finding roots:
For function y(t) to be bounded when we need for both roots of the auxiliary equation to be non-positive if they are reals and, if they are complex, then the real part has to be non-positive. In other words
Given that, the volume of both tanks is 100 L. Then, the fluid is flowing from tank A to tank B at the rate of 3 L/min and from B into A at a rate of 1 L/min.
A brine solution with a concentration of 0.2 kg/L of salt flows into tank A at a rate of 6 L/min.
The solution flows out of the system from tank A at 4 L/min and from tank B at 2 L/min.
Let us take, the amount of salt in tank A be x(t) kg and the amount of salt in tank B be y(t) kg.
Then, and .
Let us create the system of equations first.
For tank A:
Rate of inflow
Rate of outflow
For tank B:
Rate of inflow
Rate of outflow
Multiply 0.03 on equation (3) and multiply D+0.07 on equation (4). Then, subtract them together.
Since the auxiliary equation to the corresponding homogeneous equation is .
Then,
So, the roots are and .
Then, the general solution of y is
Let us assume that,
Substitute equation (7) in equation (5).
Substitute the value of C in equations (7) and y(t).
So,
Now substitute equation (8) in equation (4).
Given that, and .
Substitute the values in equations (8) and (9).
Case (1):
Hence,
Case (2):
Thereafter,
Solve the equation (a) and (b).
Substitute the value of A in equation (b).
Finally, substitute the values of A and B in equations (8) and (9).
Therefore, the solution is founded.
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