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Use the method of this section to solve each linear programming problem. $$ \begin{aligned} \text { Minimize } & C=x+2 y \\ \text { subject to } & 4 x+7 y \leq 70 \\ & 2 x+y=20 \\ & x \geq 0, y \geq 0 \end{aligned} $$

Short Answer

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The solution to the given linear programming problem is to minimize the cost function \(C = x + 2y\), subject to the constraints \(4x + 7y \leq 70\), \(2x + y = 20\), and \(x \geq 0\), \(y \geq 0\). By graphing the constraints and finding the vertices of the feasible region, we find four vertices: \((0, 0)\), \((10, 0)\), \((8, 4)\), and \((0, 10)\). Evaluating the cost function at each vertex, we find that the minimum value of the cost function is \(C_{min} = 0\) at \((x, y) = (0, 0)\).
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Step 1: Graph constraints and find feasible region

First, let's graph the constraints: \(4x + 7y \leq 70\) \(2x + y = 20\) \(x \geq 0\) \(y \geq 0\) After graphing, the feasible region is the area where all constraints are satisfied, bounded by the respective lines.

Step 2: Determine the vertices of the feasible region

Observe the feasible region in the graph. The vertices are the points of intersection of the respective lines. There are a total of 4 vertices: 1. Intersection of \(x=0\) and \(y=0\) 2. Intersection of \(y=0\) and \(2x + y = 20\) 3. Intersection of \(4x + 7y \leq 70\) and \(2x + y = 20\) 4. Intersection of \(x=0\) and \(4x + 7y \leq 70\) Now, find the coordinates of these vertices: 1. Vertex 1: \((0, 0)\) 2. Vertex 2: Solve the system of equations \(y=0\) and \(2x + y = 20\) to get \((10, 0)\) 3. Vertex 3: Solve the system of equations \(4x + 7y = 70\) and \(2x + y = 20\) to get \((8, 4)\) 4. Vertex 4: Solve the system of equations \(x=0\) and \(4x + 7y = 70\) to get \((0, 10)\)

Step 3: Calculate the cost function at each vertex

Now, we will evaluate the cost function \(C = x + 2y\) for every vertex: 1. Vertex 1: \(C(0, 0) = 0\) 2. Vertex 2: \(C(10, 0) = 10\) 3. Vertex 3: \(C(8, 4) = 16\) 4. Vertex 4: \(C(0, 10) = 20\)

Step 4: Identify the minimum value of the cost function

Finally, we will compare the values of the cost function at each vertex to determine the minimum value: - Vertex 1: \(C = 0\) - Vertex 2: \(C = 10\) - Vertex 3: \(C = 16\) - Vertex 4: \(C = 20\) As we can see, the minimum value of the cost function is at Vertex 1, with \(C=0\) being the minimum value. Therefore, the solution to this linear programming problem is \(C_{min} = 0\), at \((x, y) = (0, 0)\).

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Most popular questions from this chapter

Chapter 4

Steinwelt Piano manufactures uprights and consoles in two plants, plant I and plant II. The output of plant I is at most \(300 /\) month, whereas the output of plant II is at most \(250 /\) month. These pianos are shipped to three warehouses that serve as distribution centers for the company. To fill current and projected orders, warehouse A requires a minimum of 200 pianos/month, warehouse B requires at least 150 pianos/month, and warehouse \(\mathrm{C}\) requires at least 200 pianos/month. The shipping cost of each piano from plant I to warehouse A, warehouse \(\mathrm{B}\), and warehouse \(\mathrm{C}\) is $\$ 60, \$ 60\(, and \)\$ 80$, respectively, and the shipping cost of each piano from plant II to warehouse A, warehouse B, and warehouse \(\mathrm{C}\) is $\$ 80, \$ 70\(, and \)\$ 50$, respectively. Use the method of this section to determine the shipping schedule that will enable Steinwelt to meet the warehouses' requirements while keeping the shipping costs to a minimum.

Chapter 4

Rewrite each linear programming problem as a maximization problem with constraints involving inequalities of the form \(\leq\) a constant (with the exception of the inequalities \(x \geq 0, y \geq 0\), and \(z \geq 0\) ). $$ \begin{array}{ll} \text { Maximize } & P=2 x+y-2 z \\ \text { subject to } & x+2 y+z \geq 10 \\ & 3 x+4 y+2 z \geq 5 \\ & 2 x+5 y+12 z \leq 20 \\ & x \geq 0, y \geq 0, z \geq 0 \end{array} $$

Chapter 4

Solve each linear programming problem by the simplex method. $$ \begin{array}{cc} \text { Maximize } & P=3 x+4 y+5 z \\ \text { subject to } & x+y+z \leq 8 \\ & 3 x+2 y+4 z \leq 24 \\ x & \geq 0, y \geq 0, z \geq 0 \end{array} $$

Chapter 4

Solve each linear programming problem by the simplex method. $$ \begin{array}{lr} \text { Maximize } & P=x+4 y-2 z \\ \text { subject to } & 3 x+y-z \leq 80 \\ & 2 x+y-z \leq 40 \\ & -x+y+z \leq 80 \\ x & \geq 0, y \geq 0, z & \geq 0 \end{array} $$

Chapter 4

Use the method of this section to solve each linear programming problem. $$ \begin{array}{ll} \text { Maximize } & P=5 x+y \\ \text { subject to } & 2 x+y \leq 8 \\ & -x+y \geq 2 \\ & x \geq 0, y \geq 0 \end{array} $$

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