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Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=3 x+4 y \\ \text { subject to } & x+y \leq 4 \\ & 2 x+y \leq 5 \\ & x \geq 0, y \geq 0 \end{array} $$

Short Answer

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The optimal solution is \(x = 0\), \(y = 1\), yielding the maximum value for the objective function \(P = 4\).
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Step 1: Convert inequalities to equations by adding slack variables

Introduce slack variables s1 and s2 to convert the inequality constraints into equations: 1. \(x + y + s_1 = 4\) 2. \(2x + y + s_2 = 5\) Now, we have the following linear system with non-negative variables: $$ \begin{cases} x + y +s_1 = 4 \\ 2x + y +s_2 = 5\\ x \geq 0, y \geq 0, s_1 \geq 0, s_2 \geq 0 \\ \text{Maximize } P = 3x + 4y \\ \end{cases} $$

Step 2: Setup the initial tableau

Convert the linear system into an initial simplex tableau: $$ \begin{array}{c|cccc|c} & x & y & s_1 & s_2 & \text{RHS (Right Hand Side)} \\ \hline \text{P} & -3 & -4 & 0 & 0 & 0\\ s_1 & 1 & 1 & 1 & 0 & 4\\ s_2 & 2 & 1 & 0 & 1 & 5 \end{array} $$

Step 3: Perform pivot operations to obtain an optimal solution

Identify the entering variable: Since we need to maximize the objective function P, we choose the variable with the most negative coefficient in the objective function row, which is y. Identify the leaving variable: Divide the RHS by the positive coefficients of y in each constraint to find the minimum non-negative ratio: \( s_1: \frac{4}{1} = 4 \\ s_2: \frac{5}{1} = 5 \\ \) y will enter, and s1 will leave. Perform the pivot operation on element (2,2): $$ \begin{array}{c|cccc|c} & x & y & s_1 & s_2 & \text{RHS} \\ \hline \text{P} & 1 & 0 & 4 & 0 & 16 \\ s_1 & 1 & 1 & 1 & 0 & 4 \\ s_2 & 0 & 1 & -2 & 1 & 1 \end{array} $$ Now, we must check if there is a more negative coefficient in the objective function row. There are no more negative coefficients, indicating that the optimal solution has been found.

Step 4: Interpret the tableau to find the optimal solution

To obtain the final solution, we'll take the values of the variables from the tableau. We'll assign the values of the non-basic variables (s1 and s2) as 0: s_1 = 4 (basic variable - leaving variable) \\ s_2 = 0 (non-basic variable) \\ x = 0 (basic variable) \\ y = 1 (non-basic variable - entering variable) So, the optimal solution is \(x = 0\), \(y = 1\), which yields the maximum value for P, \(P = 3(0) + 4(1) = 4\).

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Most popular questions from this chapter

Chapter 4

Wayland Company manufactures two models of its twin-size futons, standard and deluxe, in two locations, I and II. The maximum output at location I is 600 /week, whereas the maximum output at location II is \(400 /\) week. The profit per futon for standard and deluxe models manufactured at location I is \(\$ 30\) and \(\$ 20\), respectively; the profit per futon for standard and deluxe models manufactured at location II is \(\$ 34\) and \(\$ 18\), respectively. For a certain week, the company has received an order for 600 standard models and 300 deluxe models. If prior commitments dictate that the number of deluxe models manufactured at location II not exceed the number of standard models manufactured there by more than 50 , find how many of each model should be manufactured at each location so as to satisfy the order and at the same time maximize Wayland's profit.

Chapter 4

A company manufactures products \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\). Each product is processed in three departments: I, II, and III. The total available labor-hours per week for departments I, II, and III are 900,1080 , and 840 , respectively. The time requirements (in hours per unit) and profit per unit for each product are as follows: $$ \begin{array}{lccc} \hline & \text { Product A } & \text { Product B } & \text { Product C } \\ \hline \text { Dept. I } & 2 & 1 & 2 \\ \hline \text { Dept. II } & 3 & 1 & 2 \\ \hline \text { Dept. III } & 2 & 2 & 1 \\ \hline \text { Profit } & \$ 18 & \$ 12 & \$ 15 \\ \hline \end{array} $$ How many units of each product should the company produce in order to maximize its profit? What is the largest profit the company can realize? Are there any resources left over?

Chapter 4

Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=4 x+6 y \\ \text { subject to } & 3 x+y \leq 24 \\ & 2 x+y \leq 18 \\ & x+3 y \leq 24 \\ & x \geq 0, y \geq 0 \end{array} $$

Chapter 4

Use the method of this section to solve each linear programming problem. $$ \begin{aligned} \text { Minimize } & C=x-2 y+z \\ \text { subject to } & x-2 y+3 z \leq 10 \\ 2 x+y-2 z & \leq 15 \\ & 2 x+y+3 z \leq 20 \\ & x \geq 0, y \geq 0, z \geq 0 \end{aligned} $$

Chapter 4

You are given the final simplex tableau for the dual problem. Give the solution to the primal problem and the solution to the associated dual problem. Problem: Minimize \(\quad C=8 x+12 y\) subject to $\begin{aligned} x+3 y & \geq 2 \\ 2 x+2 y & \geq 3 \\ x \geq 0, y & \geq 0 \end{aligned}$ $$ \begin{array}{rrrrr|c} u & v & x & y & P & \text { Constant } \\ \hline 0 & 1 & \frac{3}{4} & -\frac{1}{4} & 0 & 3 \\ 1 & 0 & -\frac{1}{2} & \frac{1}{2} & 0 & 2 \\ \hline 0 & 0 & \frac{5}{4} & \frac{1}{4} & 1 & 13 \end{array} $$

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