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You are given the final simplex tableau for the dual problem. Give the solution to the primal problem and the solution to the associated dual problem. Problem: Minimize \(\quad C=2 x+3 y\) subject to $\begin{aligned} x+4 y & \geq 8 \\ x+y & \geq 5 \\ 2 x+y & \geq 7 \\\ x \geq 0, y & \geq 0 \end{aligned}$ Final tablcau: $$ \begin{array}{cccccc|c} u & v & w & x & y & P & \text { Constant } \\ \hline 0 & 1 & \frac{7}{3} & \frac{4}{3} & -\frac{1}{3} & 0 & \frac{5}{5} \\ 1 & 0 & -\frac{1}{3} & -\frac{1}{3} & \frac{1}{3} & 0 & \frac{1}{3} \\ \hline 0 & 0 & 2 & 4 & 1 & 1 & 11 \end{array} $$

Short Answer

Expert verified
The solution to the primal problem is \((x, y) = (\frac{1}{3}, \frac{5}{3})\) with the minimum value of the objective function \(C = \frac{17}{3}\). The solution to the dual problem is \((u, v, w) = (1, 0, \frac{7}{3})\) with the maximum value of the objective function \(W = \frac{65}{3}\).
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Step 1: Identify the primal and dual problems

The given problem is a minimization problem; the primal problem is: Minimize \(C=2x + 3y\) subject to: \(x + 4y \geq 8\) \(x + y \geq 5\) \(2x + y \geq 7\) \(x, y \geq 0\) Now, let's write the dual problem: Maximize \(W=8u + 5v + 7w\) subject to: \(u + v + 2w \leq 2\) \(4u + v + w \leq 3\) \(u, v, w \geq 0\)

Step 2: Identify the optimal solution for both primal and dual problems from the final simplex tableau

The final simplex tableau is: $$ \begin{array}{cccccc|c} u & v & w & x & y & P & \text { Constant } \\ \hline 0 & 1 & \frac{7}{3} & \frac{4}{3} & -\frac{1}{3} & 0 & \frac{5}{3} \\ 1 & 0 & -\frac{1}{3} & -\frac{1}{3} & \frac{1}{3} & 0 & \frac{1}{3} \\ \hline 0 & 0 & 2 & 4 & 1 & 1 & 11 \end{array} $$ From the tableau, we can find the optimal solution for both primal and dual problems: For the primal problem: \(x = \frac{1}{3}\) \(y=\frac{5}{3}\) \(C_{min} = 2(\frac{1}{3}) + 3(\frac{5}{3}) = \frac{2}{3} + 5 = \frac{17}{3}\) The solution to the primal problem is \((x, y) = (\frac{1}{3}, \frac{5}{3})\) and the minimum value of C is \(\frac{17}{3}\). For the dual problem: \(u=1\) \(v=0\) \(w=\frac{7}{3}\) \(W_{max} = 8(1) + 5(0) + 7(\frac{7}{3}) = 8 + \frac{49}{3} = \frac{65}{3}\) The solution to the dual problem is \((u, v, w) = (1, 0, \frac{7}{3})\) and the maximum value of W is \(\frac{65}{3}\).

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Most popular questions from this chapter

Chapter 4

Use the method of this section to solve each linear programming problem. $$ \begin{aligned} \text { Minimize } & C=-2 x+3 y \\ \text { subject to } & x+3 y \leq 60 \\ 2 x+y & \geq 45 \\ x & \leq 40 \\ x \geq 0, y & \geq 0 \end{aligned} $$

Chapter 4

Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=5 x+4 y \\ \text { subject to } & 3 x+5 y \leq 78 \\ & 4 x+y \leq 36 \\ & x \geq 0, y \geq 0 \end{array} $$

Chapter 4

You are given the final simplex tableau for the dual problem. Give the solution to the primal problem and the solution to the associated dual problem. Problem: Minimize \(C=3 x+2 y\) subject to $\begin{aligned} 5 x+y & \geq 10 \\ 2 x+2 y & \geq 12 \\ x+4 y & \geq 12 \\ x \geq 0, y & \geq 0 \end{aligned}$ Final tablcau: $$ \begin{array}{rrrrrr|r} u & v & w & x & y & P & \text { Constant } \\ \hline 1 & 0 & -\frac{1}{4} & \frac{1}{4} & -\frac{1}{4} & 0 & \frac{1}{4} \\ 0 & 1 & \frac{19}{8} & -\frac{1}{8} & \frac{5}{8} & 0 & \frac{7}{8} \\ \hline 0 & 0 & 9 & 1 & 5 & 1 & 13 \end{array} $$

Chapter 4

Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=3 x+4 y+z \\ \text { subject to } & 3 x+10 y+5 z \leq 120 \\ & 5 x+2 y+8 z \leq 6 \\ & 8 x+10 y+3 z \leq 105 \\ & x \geq 0, y \geq 0, z \geq 0 \end{array} $$

Chapter 4

A veterinarian has been asked to prepare a diet for a group of dogs to be used in a nutrition study at the School of Animal Science. It has been stipulated that each serving should be no larger than \(8 \mathrm{oz}\) and must contain at least 29 units of nutrient \(I\) and 20 units of nutrient II. The vet has decided that the diet may be prepared from two brands of dog food: brand \(\mathrm{A}\) and brand \(\mathrm{B}\). Each ounce of brand A contains 3 units of nutrient \(\mathrm{I}\) and 4 units of nutrient II. Each ounce of brand \(B\) contains 5 units of nutrient I and 2 units of nutrient II. Brand \(A\) costs 3 cents/ounce and brand B costs 4 cents/ounce. Determine how many ounces of each brand of dog food should be used per serving to meet the given requirements at minimum cost.

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