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Problem 11

In Exercises \(9-14, X\) has a normal distribution with the given mean and standard deviation. Find the indicated probabilities. $$ \mu=50, \sigma=10, \text { find } P(30 \leq X \leq 62) $$

Expert verified

The probability of X lying between 30 and 62 in this normal distribution is approximately \( P(30 \leq X \leq 62) = 0.8621 \) or 86.21%.

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