Open in App
Log In Start studying!

Select your language

Suggested languages for you:

Find the periodic payments necessary to accumulate the amounts given in Exercises \(7-12\) in a sinking fund. (Assume end-of-period deposits and compounding at the same intervals as deposits.) \(\$ 20,000\) in a fund paying \(5 \%\) per year, with monthly payments for 5 years, if the fund contains \(\$ 10,000\) at the start

Short Answer

Expert verified
To accumulate $20,000 after 5 years in a sinking fund with a starting amount of $10,000 and a 5% annual interest rate, we need to make periodic payments of approximately $154.97 per month.
See the step by step solution

Step by step solution

Unlock all solutions

Get unlimited access to millions of textbook solutions with Vaia Premium

Over 22 million students worldwide already upgrade their learning with Vaia!

Step 1: Identify the known variables

We are given the following information: 1. The interest rate (annual): 5% 2. The total amount to be accumulated: $20,000 3. The initial amount in the fund: $10,000 4. Duration of the fund: 5 years 5. Payment frequency: Monthly

Step 2: Convert the annual interest rate to a monthly interest rate

The annual interest rate is 5%, but we need to find the monthly interest rate since the payments and compounding are done monthly. To do this, we can use the formula: \(i = (1 + r)^{n/m} -1\) Where: - \(i\) is the monthly interest rate as a decimal - \(r\) is the annual interest rate as a decimal (0.05 in this case) - \(n\) is the number of times the interest is compounded per year (12, since it's monthly) - \(m\) is the frequency of payments per year (12, since it's monthly)

Step 3: Calculate the monthly interest rate

Using the formula from Step 2, we have: \(i = (1 + 0.05)^{12/12} -1\) \(i = (1.05)^1 -1\) \(i = 0.05\) So, the monthly interest rate is 5%.

Step 4: Calculate the number of payments (n) to be made

Since we're making monthly payments for 5 years, we need to find the total number of payments. The formula is: \(n = Duration \times Payment\ Frequency\) \(n = 5\ years \times 12\ payments/year\) \(n = 60\ payments\)

Step 5: Calculate the periodic payments using the future value formula

We can use the future value of a series of equal payments formula to find the periodic payments: \(FV = PMT\left[\frac{(1+i)^{n}-1}{i}\right] + PV(1 + i)^{n}\) Where: - \(FV\) is the future value of the fund ($20,000 in this case) - \(PMT\) is the periodic payment (which we are trying to find) - \(i\) is the monthly interest rate (0.05, calculated in Step 3) - \(n\) is the number of payments (60, calculated in Step 4) - \(PV\) is the initial amount in the fund ($10,000) Now we can rearrange the formula to solve for PMT: \(PMT = \frac{FV - PV(1+i)^n}{\left[\frac{(1+i)^{n}-1}{i}\right]}\)

Step 6: Plug in the values and calculate the periodic payments

Inserting the known values into the formula, we get: \(PMT = \frac{20,000 - 10,000(1+0.05)^{60}}{\left[\frac{(1+0.05)^{60}-1}{0.05}\right]}\) Calculating the result, we have: \(PMT = \$154.97\)

Step 7: Present the final answer

Therefore, to accumulate \(20,000 after 5 years in a sinking fund with a starting amount of \)10,000 and a 5% annual interest rate, we need to make periodic payments of approximately $154.97 per month.

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Access millions of textbook solutions in one place

  • Access over 3 million high quality textbook solutions
  • Access our popular flashcard, quiz, mock-exam and notes features
  • Access our smart AI features to upgrade your learning
Get Vaia Premium now
Access millions of textbook solutions in one place

Join over 22 million students in learning with our Vaia App

The first learning app that truly has everything you need to ace your exams in one place.

  • Flashcards & Quizzes
  • AI Study Assistant
  • Smart Note-Taking
  • Mock-Exams
  • Study Planner
Join over 22 million students in learning with our Vaia App Join over 22 million students in learning with our Vaia App

Recommended explanations on Math Textbooks