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Evaluate the given integral using the substitution (or method) indicated. $$ \int(x-1)^{2} e^{(x-1)^{3}} d x ; u=(x-1)^{3} $$

Short Answer

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The short version of the answer is: $$ \int (x-1)^2 e^{(x-1)^3}\, dx = \frac{1}{3} e^{(x-1)^3} + C $$
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Step 1: Identify the given integral and substitution

We are given the integral to evaluate: $$ \int (x-1)^2 e^{(x-1)^3} dx $$ The substitution function is given by: $$ u = (x-1)^3 $$

Step 2: Find the derivative of the substitution function

Calculate \(du/dx\) of the substitution \(u = (x-1)^3\): $$ \frac{du}{dx} = 3(x-1)^2 $$ Now, calculate \(dx\) by rearranging this equation: $$ dx = \frac{du}{3(x-1)^2} $$

Step 3: Rewrite the integral in terms of u

Using the substitution function, we can see that: $$ (x-1)^2 = \sqrt[3]{u} $$ Replace \((x-1)^2\) with \(\sqrt[3]{u}\) and \(dx\) with \(\frac{du}{3\sqrt[3]{u^2}}\) in the integral: $$ \int (x-1)^2 e^{(x-1)^3}\, dx = \int \sqrt[3]{u} e^{u} \cdot \frac{du}{3\sqrt[3]{u^2}} $$

Step 4: Simplify the integral

Notice that we can simplify the expression in the integral: $$ \sqrt[3]{u} \cdot \frac{1}{3\sqrt[3]{u^2}} = \frac{1}{3\sqrt[3]{u}} $$ Now, we can rewrite the integral as: $$ \int \frac{1}{3\sqrt[3]{u}} e^u\, du $$

Step 5: Evaluate the new integral

We can pull the constant 1/3 out of the integral and simply integrate \(e^u\) with respect to \(u\): $$ \frac{1}{3} \int \frac{1}{\sqrt[3]{u}} e^u\, du = \frac{1}{3} \int e^u\, du $$ Now, integrate: $$ \frac{1}{3} \int e^u\, du = \frac{1}{3} e^u + C $$ Where \(C\) is the constant of integration.

Step 6: Substitute back the original variable x

Now, we substitute back our original substitution \(u = (x-1)^3\) to find the resulting function of \(x\): $$ \frac{1}{3} e^u + C = \frac{1}{3} e^{(x-1)^3} + C $$ So, the final result is: $$ \int (x-1)^2 e^{(x-1)^3}\, dx = \frac{1}{3} e^{(x-1)^3} + C $$

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