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Evaluate the expressions. $$ \left(\frac{-2}{3}\right)^{-2} $$

Short Answer

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The short answer is: \(\left(\frac{-2}{3}\right)^{-2} = \left(\frac{3}{-2}\right)^{2} = \frac{9}{4}\).
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Step by step solution

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Step 1: Evaluate the negative exponent

Recall that a number raised to the power of a negative exponent is equal to the reciprocal of the number raised to the positive exponent: $$ \left(a^{-n}\right) = \frac{1}{a^n} $$ Using this rule, we find the reciprocal of the fraction and raise it to the power of 2: $$ \left(\frac{-2}{3}\right)^{-2} = \left(\frac{3}{-2}\right)^{2} $$

Step 2: Simplify the expression

Now, raise the fraction to the power of 2 by squaring both the numerator and the denominator: $$ \left(\frac{3}{-2}\right)^{2} = \frac{3^2}{(-2)^2} $$ Then compute the squares of 3 and -2: $$ \frac{3^2}{(-2)^2} = \frac{9}{4} $$ The final result is \(\frac{9}{4}\).

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