Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


Essential Calculus: Early Transcendentals
Found in: Page 556
Essential Calculus: Early Transcendentals

Essential Calculus: Early Transcendentals

Book edition 2nd
Author(s) James Stewart
Pages 830 pages
ISBN 9781133112280

Answers without the blur.

Just sign up for free and you're in.


Short Answer

To find a dot product between \({\rm{a}}\) and \({\rm{b}}\).

The dot product \(a \cdot b\) is \( - pq\)

See the step by step solution

Step by Step Solution

Step 1: Concept of the Dot Product

The minimum of two vectors are required to perform a dot product. The resultant dot product of two vectors is scalar. hence, the dot product is also known as a scalar product.

Step 2: Calculation of the dot product

The given two vectors are\({\rm{a}} = \langle p, - p,2p\rangle \) and \({\rm{b}} = \langle 2q,q, - q\rangle \)

Consider a general expression to find the dot product between two three-dimensional vectors.

\(\begin{aligned}{l}{\rm{a}} \cdot {\rm{b}} &= \left\langle {{a_1},{a_2},{a_3}} \right\rangle \cdot \left\langle {{b_1},{b_2},{b_3}} \right\rangle \\{\rm{a}} \cdot {\rm{b}} &= {a_1}{b_1} + {a_2}{b_2} + {a_3}{b_3}\end{aligned}\)

Substitute \(p\) for \({a_1}, - p\) for \({a_2},2p\) for \({a_3},2q\) for \({b_1},q\) for \({b_2}\) and \( - q\) for \({b_3}\).

\(\begin{aligned}{l}{\rm{a}} \cdot {\rm{b}} &= (p)(2q) + ( - p)(q) + (2p)( - q)\\{\rm{a}} \cdot {\rm{b}} &= 2pq - pq - 2pq\\{\rm{a}} \cdot {\rm{b}} &= - pq\end{aligned}\)

Thus, \(a \cdot b\) is \( - pq\).

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.