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Q. 107

Expert-verified

Elementary Algebra

Found in: Page 229

Book edition 2nd

Author(s) Lynn Marecek, MaryAnne Anthony-Smith

Pages 1240 pages

ISBN 9780998625713

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Short Answer

In the following exercise, solve each equation using the Division and Multiplication Properties of Equality and check the solution.
$- \frac{7}{10} x = - \frac{14}{3}$

On solving, we get $x = \frac{20}{3} .$

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information

$\begin{array}{l} The given equation is - \frac{7}{10} x = - \frac{14}{3} . \\ We have to solve the given equation and then verify the result. \end{array}$

Step 2. Simplify

$\begin{array}{l} Now, \\ \Rightarrow - \frac{7}{10} x = - \frac{14}{3} \\ \Rightarrow - \frac{10}{7} \times (- \frac{7}{10} x) = - \frac{10}{7} \times (- \frac{14}{3}) [Multiply both sides by reciprocal of - \frac{7}{10}] \\ \Rightarrow x = \frac{20}{3} \end{array}$

Step 3. Checking the result

$\begin{array}{l} We have, \\ \Rightarrow - \frac{7}{10} x = - \frac{14}{3} \\ \Rightarrow - \frac{7}{10} (\frac{20}{3}) = - \frac{14}{3} [Substitute x = \frac{20}{3}] \\ \Rightarrow - \frac{7}{10} \times \frac{2 \times 10}{3} = - \frac{14}{3} \\ \Rightarrow - \frac{14}{3} = - \frac{14}{3} \\ L.H.S = R.H.S \\ Hence verified. \end{array}$

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