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Q 43.

Expert-verifiedFound in: Page 801

Book edition
1st

Author(s)
Peter Kohn, Laura Taalman

Pages
1155 pages

ISBN
9781429241861

Find a vector in the direction of$>">3,1,2$ and with magnitude 5.

The required vector is $\frac{5}{\sqrt{14}}>">3,1,2$.

The given vector is:

$\mathit{v}=>">3,1,2$ with magnitude 5.

$\mathit{v}=>">3,1,2$

Therefore, the norm of the given vector is $\sqrt{14}$.

We know that the vector in the direction of **v **is $\frac{a}{||\mathit{v}||}\mathit{v}$. Here * a *is the magnitude of the given vector.

The required vector is:

$\frac{a}{||\mathit{v}||}\mathit{v}=\frac{5}{\sqrt{14}}>">3,1,2$

Therefore the vector in the direction of $\mathit{v}=>">3,1,2$ and with a magnitude of 5 is $\frac{5}{\sqrt{14}}>">3,1,2$.

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