Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q. 5

Expert-verified
Calculus
Found in: Page 879
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Under what conditions does a differentiable vector-valued function r(t) not have a unit tangent vector at a point in the domain of r(t)?

A differentiable vector-valued function r(t) does not have a unit tangent vector at any point t0 in the domain of r(t) at which r't0=0.

See the step by step solution

Step by Step Solution

Step 1. Given Information.

The definition of the unit tangent vector is to let r(t) be a differentiable vector function on some interval I such that r'(t)0 on I. The unit tangent function is defined to be Tt=r'(t)r'(t).

Step 2. Explanation.

Let t0 be any point in the domain of r(t). So, by the definition of unit tangent vector, r(t) does not contain a unit tangent vector at any point t0 at which r't0=0.

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.