Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q. 0

Expert-verified
Calculus
Found in: Page 930
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Problem Zero: Read the section and make your own summary of the material.

Summary of the section 12.2 includes Open sets and closed sets, Limit of a function and Continuity of a function.

See the step by step solution

Step by Step Solution

Step 1. Open sets and closed sets

Section 12.2 covers the concepts of open sets, closed sets, the limit of a function, and the continuity of a function.

To understand the concept of open sets, we first need to understand what an open disk or ball is. An open disk in $$\mathbb{R}^ 2 $$ is a subset of the form $$\{ (x,y) | (x-x_{0})^2+(y-y_{0})^2 < \epsilon \}$$A open ball in $$\mathbb{R}^ 3 $$ is a subset of the form $$\{ (x,y,z) | (x-x_{0})^2+(y-y_{0})^2 +(z-z_{0})^2 < \epsilon \}$$A subset $$S$$ of $$\mathbb{R}^ 2 $$ or $$\mathbb{R}^ 3 $$ is said to be open if, for every point $$(x,y)$$ or $$(x,y,z)$$ in $$S$$there exists a open disk $$D$$ or ball $$B$$ such that $$D \in S$$ or $$B \in S$$A closed set is a set whose complement is open. i.e for $$A$$ to be a closed set, $$A^{c}$$ must be open.

Let $$S$$ be a subset of $$\mathbb{R}^ 2 $$ or $$\mathbb{R}^ 3 $$ A point $$(x,y)$$ or $$(x,y,z)$$ in $$S$$ is said to be a boundary point if every open disk or ball containing it intersects both $$S$$ and $$S^{c}$$The set of all boundary points of $$S$$ is called the boundary of $$S$$A subset of $$\mathbb{R}^ 2 $$ or $$\mathbb{R}^ 3 $$ is said to be bounded if it is a subset of some open disk or ball in $$\mathbb{R}^ 2 $$ or $$\mathbb{R}^ 3$$ A subset which is not bounded is said to be unbounded.

Step 2. Limit of a function

Let $$f$$ be a function of two or more variables. The limit of $$f$$ at $$a$$ is $$L$$ if, for every $$ \epsilon > 0$$there exists $$ \delta >0$$such that $$ | f-L|<\epsilon$$ whenever $$0 < |x-a|<\delta$$Then we can write \[ \lim_{x\to a} f(x) = L \]In the case where $$f$$ is a function is two variables, $$ x= \langle (x,y) \rangle $$ and $$ a= \langle (a,b) \rangle $$Therefore \[ \lim_{x\to a} f(x) = L \] means $$ | f(x,y)-L|<\epsilon$$ whenever $$0 < \sqrt{(x-a)^2+(y-b)^2}<\delta$$. In the case where $$f$$ is a function is three variables, $$ x= \langle (x,y,z) \rangle $$ and $$ a= \langle (a,b,c) \rangle $$. Therefore \[ \lim_{x\to a} f(x) = L \] means $$ | f(x,y,z)-L|<\epsilon$$ whenever $$0 < \sqrt{(x-a)^2+(y-b)^2+(z-c)^2}<\delta$$

Algebra of limits of function in one variable can be applied directly to the functions of two or more variables.

The limit of a function in two or more variables exists if and only if the the limit is same for every path containing the given point. i.e. the limit \[ \lim_{x\to a} f(x) = L \] exists if and only if \[ \lim_{x\to a} f(x) = L \] for every path $$C$$ containing $$(a,b)$$ in open set $$S$$.

Step 3.  Continuity of a function

A function $$f$$ in two or more variables defined over an open set $$S$$ is said to be continuous at a point $$a$$ in $$S$$ if \[ \lim_{x\to a} f(x) = f(a) \]. Also, $$f$$ is continuous on $$S$$ if it is continuous on every point in $$S$$ A function is said to be continuous everywhere if it is continuous at every point of it's domain.

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.