Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q1

Expert-verified
Calculus
Found in: Page 197
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: ddx(5)=0(b) True or False: ddr(ks+r)=k(c) True or False: dds(ks+r)=k(d) True or False: ddx(3x+1)k=k(3x+1)k-1 (e) True or False: ddx1x3=13x2(f) True or False : If f and g are differentiable functions, then (f(x)g(x))'=g'(x)f(x)+f'(x)g(x)(g) True or False : If f and g are differentiable functions, theng(x)h(x)'=h(x)g'(x)-g(x)h'(x)(h(x))2(h)True or False: Proving the sum rule for differentiation involves the definition of the derivative , a lot of algebrac manipuations and the sum rule for limits

(a) The given statement is true as derivative of constant is 0

(b) The given statement is false because the derivative is 1

(c) The given statement is true because derivative is k

(d) The given statement is false because the derivative of 3x+1 is not taken .

(e) The derivative is not same. the given statement is false.

(f) The given statement is true because it represent the product rule

(g) The given statement is true because it represent the Quotient rule

(h) The given statement is true because the sum rule of limit is used for proving the sum rule of differentiation

See the step by step solution

Step by Step Solution

step 1:Given Information 

Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

Part (a): Step 1 : Derivative

Derivative of a constant is 0.

ddx(5)=0

The given statement is true as derivative of constant is 0

Part(b): Step 1: Derivative 

ddr (ks + r) = k ddr (ks + r) =ddr ks +ddr r=0+1=1 ddr (ks + r) = 1

The given statement is false because the derivative is 1

Part(c): Step 1: Derivative 

dds (ks + r) = k dds (ks + r) = dds(ks)+dds(r)=k+0=k

The given statement is true because derivative is k

Part(d) : Step 1: Derivative

ddx(3x+1)k=k(3x+1)k-1 ddx(3x+1)k=k(3x+1)k-1*(3)=3k(3x+1)k-1

The given statement is false because the derivative for 3x+1 is not multiplied.

Part(e): Step 1 : Derivative 

ddx( 1x3)=13x2ddx(1/x3) =ddx(x-3)-3x(-3-1)=-3 x3

The derivative is not same. the given statement is false.

Part f: step 1: Derivative 

( f (x)g(x))' = g'(x)f (x) + f '(x)g(x)

The given statement is true because it represents the product rule

Part(g): Step 1 Derivative 

If g and h are differentiable functions, then

g(x)h(x)'=(h(x)g'(x)-g(x)h'(x))(h(x)2)

The given statement is true because it represent the Quotient rule

Part(h): Step 1 : Derivative

Proving the sum rule for differentiation involves the definition of the derivative, a lot of algebraic manipulation, and the sum rule for limits.

The given statement is true because the sum rule of limit is used for proving the sum rule of differentiation .

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.