Suggested languages for you:

Americas

Europe

Q. 15

Expert-verifiedFound in: Page 510

Book edition
1st

Author(s)
Peter Kohn, Laura Taalman

Pages
1155 pages

ISBN
9781429241861

For each pair of definite integrals in exercise 13-18 decide which if either is larger without computing the integrals

$\pi {\int}_{0}^{2}{x}^{4}dxand\pi {\int}_{0}^{2}({x}^{4}-16)dx$

The integral $\pi {\int}_{0}^{2}{x}^{4}dx$ is bigger

We are given two integrals

$\pi {\int}_{0}^{2}{x}^{4}dxand\pi {\int}_{0}^{2}({x}^{4}-16)dx$

The term ${x}^{4}isbiggerthanterm{x}^{4}-16$

Hence on integrating we will get the term 16x in second integral And after substituting the limits the second term will be 16 less than that of first term. Hence the first term is bigger

94% of StudySmarter users get better grades.

Sign up for free