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Given that \(\log 3 \approx 0.4771\) and \(\log 4 \approx\) 0.6021, find the value of each logarithm. $$\log 12$$

Short Answer

Expert verified
The value of \(\log 12\) is approximately 1.0792.
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Step 1: Express 12 as a product of 3 and 4

We can write the number 12 as the product of 3 and 4: $$12 = 3 \times 4$$

Step 2: Apply logarithmic the product property

The logarithmic product property states that \(\log (ab) = \log a + \log b\). Applying this property, we can write the logarithm of 12: $$\log 12 = \log (3 \times 4) = \log 3 + \log 4$$

Step 3: Substitute the given values

Now, we can substitute the given values of \(\log 3\) and \(\log 4\) into the equation: $$\log 12 = 0.4771 + 0.6021$$

Step 4: Calculate the sum

Now, we just need to calculate the sum: $$\log 12 \approx 0.4771 + 0.6021 = 1.0792$$ So, the value of \(\log 12\) is approximately 1.0792.

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