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Problem 107

If \(a=3\) and \(b=2\), find \((6 a-b)^{-5 / 4}\)

Short Answer

Expert verified
\(\frac{1}{32}\)
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Step 1: Substitute the given values

We are given that \(a=3\) and \(b=2\). We start by substituting these values into the given expression \((6a-b)^{-5/4}\).

Step 2: Simplify the expression

After substituting values for \(a\) and \(b\), we get: \[(6(3)-2)^{-5/4}\] Now, simplifying the expression inside the parentheses: \[(18-2)^{-5/4}\] \[(16)^{-5/4}\]

Step 3: Evaluate the power

Now we need to evaluate the power with a negative exponent and a fraction. We can do this by breaking down the power into two parts. The \(-5/4\) power can be thought of as first raising the expression to the reciprocal of 4 and then raising to the power of -5. \[\left(16^{\frac{1}{4}}\right)^{-5}\] Now, \(16^{\frac{1}{4}}\) means the fourth root of 16, which is 2: \[(2)^{-5}\] Finally, we can evaluate the negative exponent. The power of -5 means finding the reciprocal: \[\frac{1}{2^5}\] And simplify the expression: \[\frac{1}{32}\] So the final answer is: \[(6a-b)^{-5 / 4} = \frac{1}{32}\]

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