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Convert the equation \(\mathrm{r}=\tan \theta+\cot \theta\) to an equation in cartesian coordinates.

Short Answer

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The short answer is: The given polar equation \(\mathrm{r}=\tan \theta+\cot \theta\) can be converted to the Cartesian coordinates equation \((x^2 + y^2)^{3/2} = xy\).
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Step 1: Rewrite the equation in terms of sine and cosine functions

The given equation is: \(\mathrm{r}=\tan \theta+\cot \theta\) Since we know that: \(\tan \theta = \frac{\sin \theta}{\cos \theta}\) and \(\cot \theta = \frac{\cos \theta}{\sin \theta}\), The equation becomes: \(\mathrm{r}=\frac{\sin \theta}{\cos \theta} + \frac{\cos \theta}{\sin \theta}\)

Step 2: Find a common denominator and simplify the equation

To simplify the equation, we will find a common denominator for the fractions, which is \(\cos \theta \sin \theta\). The equation now becomes: \(\mathrm{r} = \frac{\sin^2 \theta + \cos^2 \theta}{\cos \theta \sin \theta}\) As we know, \(\sin^2 \theta + \cos^2 \theta = 1\), so the equation simplifies to: \(\mathrm{r} = \frac{1}{\cos \theta \sin \theta}\)

Step 3: Substitute the polar coordinates with Cartesian coordinates

Now, we will use the polar to Cartesian coordinate transformations: \(x = r \cos \theta\) \(y = r \sin \theta\) We already have the equation: \(\mathrm{r} = \frac{1}{\cos \theta \sin \theta}\) Substitute \(\cos \theta\) with \(\frac{x}{r}\) and \(\sin \theta\) with \(\frac{y}{r}\): \(\mathrm{r} = \frac{1}{\frac{x}{r} \cdot \frac{y}{r}}\)

Step 4: Simplify the equation and solve for \(r\)

Now, simplify the equation: \(\mathrm{r} = \frac{1}{\frac{xy}{r^2}}\) \(\mathrm{r} = \frac{r^2}{xy}\) Now, multiply both sides by \(xy\): \(r^3 = x * y\)

Step 5: Substitute back Cartesian coordinates for \(r\)

Finally, replace \(r\) with \(\sqrt{x^2 + y^2}\) (since \(r^2 = x^2 + y^2\)): \((\sqrt{x^2 + y^2})^3 = xy\) This is the Cartesian equation equivalent to the given polar equation: \(x^2 + y^2)^{3/2} = xy\)

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