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Problem 324
Solve \(x+y=3\) \(2 x+3 y=1\)
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Use Cramer's rule to solve the system of equations \(3 x+y-2 z=-3\) \(2 x+7 y+3 z=9\) \(4 x-3 y-z=7\)
Solve by determinants \(2 x-y-z=-3\) \(x+y+z=6\) \(x-2 y+3 z=6\)
Show, using determinants, that the equations of the following system are dependent. $$ \begin{aligned} &5 \mathrm{x}-3 \mathrm{y}+7=0 \\ &\quad \mathrm{x}-2 \mathrm{y}=4(4 \mathrm{x}-11 / 4 \mathrm{y}+5)+1 \end{aligned} $$
Evaluate the determinant: $$ \begin{array}{rl} D= & \mid 2 & -1 & 2 \\ & \mid 3 & 3 & 6 \mid \\ 5 & 0 & -1 \end{array} \mid $$
Solve the system $$ \begin{array}{r} 2 \mathrm{x}+3 \mathrm{y}-6=0 \\ 2 \mathrm{y}=3 \mathrm{x} \end{array} $$
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