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Q69.

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Algebra 2
Found in: Page 115
Algebra 2

Algebra 2

Book edition Middle English Edition
Author(s) Carter
Pages 804 pages
ISBN 9780079039903

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Short Answer

Solve each equation. Check your solution.

69. k+7=3k-11

The solution of the equation is k=9.

See the step by step solution

Step by Step Solution

Step-1 – Apply the concept of Absolute value

On real number line, the distance of a number from 0 is the absolute value. It is always nonnegative.

The absolute value of a function is expressed as, if x is a real number then absolute value of x is defined as.

x=x when x is greater than or equal to 0 . In other words, the absolute value of x is x when x is either positive or zero.

x=-x when x is less than 0 . In other words, the absolute value of x is opposite of x when x is negative.

Step-2 –Example of Absolute value

The absolute value of 5 is expressed as 5=5 and of -5 is expressed as -5=5

Step-3 – Simplify the equation

Consider the provided equation.

k+7=3k-11

Recall the concept of absolute value and apply it.

Case 1. k+7=3k-11

Subtract k from both the sides.

k+7k=3k11k7=2k11

Subtract 7 from both the sides.

77=2k1170=2k182k=18k=9

Case 2. k+7=-3k-11

Subtract k from both the sides.

k+7k=3k+11k7=2k+11

Subtract 7 from both the sides.

77=2k+1170=2k+42k=4k=2

Therefore, there are two possible solutions for the equation k+7=3k-11 that are k=9 andk=2.

Step-4 – Verify the solutions

Substitute the value k=9 in the equation k+7=3k-11.

|9+7|=3(9)11|16|=271116=16

Since, this is true so the value k=9 satisfy the equation k+7=3k-11.

Substitute the value k=2 in the equation k+7=3k-11

|9+2|=3(2)11|11|=61111=5

Since, this is not true so the value k=2 does not satisfy the equationk+7=3k-11.

Thus, the solution set is 9.

Hence, the solution of the equation isk=9.

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