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Q. 55

Expert-verifiedFound in: Page 112

Book edition
Middle English Edition

Author(s)
Carter

Pages
804 pages

ISBN
9780079039903

$\frac{1}{4}(p-7)=\frac{1}{3}(p+5)$

$\frac{1}{4}(p-7)=\frac{1}{3}(p+5)\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{p}{4}-\frac{7}{4}=\frac{p}{3}+\frac{5}{3}\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{p}{4}-\frac{p}{3}=\frac{5}{3}+\frac{7}{4}\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{3p-4p}{12}=\frac{20+21}{12}\phantom{\rule{0ex}{0ex}}\Rightarrow -\frac{p}{12}=\frac{41}{12}\phantom{\rule{0ex}{0ex}}\Rightarrow p=-41$

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