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Q16.

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Found in: Page 15

### Algebra 2

Book edition Middle English Edition
Author(s) Carter
Pages 804 pages
ISBN 9780079039903

# Simplify each expression $\frac{1}{2}\left(16-4a\right)-\frac{3}{4}\left(12+20a\right)$

$\frac{1}{2}\left(16-4a\right)-\frac{3}{4}\left(12+20a\right)$ is simplified to $-1-17a$

See the step by step solution

## Step 1 - Write properties of real numbers

Properties of real numbers are written in following table:

 For any real numbers $a,b,$ and c: Property Addition Multiplication Commutative $a+b=b+a$ $a·b=b·a$ Associative $\left(a+b\right)+c=a+\left(b+c\right)$ $\left(a·b\right)·c=a·\left(b·c\right)$ Identity $a+0=a=0+a$ $a·1=a=1·a$ Inverse $a+\left(-a\right)=0=\left(-a\right)+a$ If $a\ne 0$, then $a·\frac{1}{a}=1=\frac{1}{a}·a$ Distributive $a\left(b+c\right)=ab+ac\text{and}\left(b+c\right)a=ba+ca$

## Step 2 - Simplify by grouping same variables

To simplify given equation, use commutative and distributive property to group coefficients of same variable as shown below

$\begin{array}{c}\frac{1}{2}\left(16-4a\right)-\frac{3}{4}\left(12+20a\right)=\left(\frac{1}{2}\cdot 16\right)-\left(\frac{1}{2}\cdot 4a\right)-\left(\frac{3}{4}\cdot 12\right)-\left(\frac{3}{4}\cdot 20a\right)\\ =8-2a-9-15a\\ =8-9-2a-15a\\ =\left(8-9\right)-\left(2+15\right)a\end{array}$

## Step 3 - Simplify parentheses

Simplify parentheses by adding or subtracting the terms as shown below

$\left(8-9\right)-\left(2+15\right)a=-1-17a$