Suggested languages for you:

Americas

Europe

Q3.

Expert-verifiedFound in: Page 226

Book edition
Middle English Edition

Author(s)
Carter

Pages
804 pages

ISBN
9780079039903

**Alejandra and Kyle both simplified$\frac{2{a}^{2}b}{{(-2a{b}^{3})}^{-2}}$ ****. Who is correct? Explain your reasoning.**

**Alejandra is correct.**

The given expression is $\frac{2{a}^{2}b}{{(-2a{b}^{3})}^{-2}}$ which is solved by both Alejandra and Kyle.

The given expression $\frac{2{a}^{2}b}{{(-2a{b}^{3})}^{-2}}$ is solved correctly by Alejandra and Kyle is not correct, because in first step Kyle wrote$\frac{2{a}^{2}b}{{(-2a{b}^{3})}^{-2}}=\frac{2{a}^{2}b}{{(-2)}^{-2}a{\left({b}^{3}\right)}^{-2}}$ instead of$\frac{2{a}^{2}b}{{(-2a{b}^{3})}^{-2}}=\frac{2{a}^{2}b}{{(-2)}^{-2}{\left(a\right)}^{-2}{\left({b}^{3}\right)}^{-2}}$ . Therefore, Kyle is incorrect because there should be${\left(a\right)}^{-2}$ in place of$\left(a\right)$ by using the concept of exponents of power property.

Hence, Alejandra is correct.

Alejandra is correct.

94% of StudySmarter users get better grades.

Sign up for free