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Q50.

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Algebra 2
Found in: Page 351
Algebra 2

Algebra 2

Book edition Middle English Edition
Author(s) Carter
Pages 804 pages
ISBN 9780079039903

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Short Answer

The graph of the polynomial function fx=axx-4x+1 passes through the point 5,15. For what value of x, fx=0.

The value of x is 0,-1 and 4 for which fx=0.

See the step by step solution

Step by Step Solution

Step 1. Write down the given information.

It is given that the graph of the polynomial function fx=axx-4x+1 passes through the point 5,15. Therefore, the point 5,15 will satisfy,

fx=axx-4x+1....1

Step 2. Calculation.

Since the graph of the polynomial function fx=axx-4x+1 passes through the point 5,15. Therefore, the point 5,15 will satisfy fx=axx-4x+1.

15=a5545+115=30aa=12

Plugging a=12 in (1),

localid="1648632935219" fx=12xx-4x+1....2

Substitute fx=0 in (2), to find the value of x, for which fx=0. Therefore from (2),

localid="1648632951759" 0=12xx4x+1xx4x+1=0x=0,x=1 and x=4

Step 3. Conclusion.

The value of x is 0,-1 and 4 for which fx=0.

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