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Q3.

Expert-verifiedFound in: Page 535

Book edition
Middle English Edition

Author(s)
Carter

Pages
804 pages

ISBN
9780079039903

**Paul and Scott are solving ${\mathrm{log}}_{3}x=9$**.

**Who is correct? Explain your reasoning.**

**Scott is correct.**

The solution for ${\mathrm{log}}_{3}x=9$ by Paul and Scott is below.

And who among Paul and Scott is correct is to be determined.

The function $a={b}^{c}$ is an exponential function and the equivalent logarithmic form is given by $c={\mathrm{log}}_{b}a$.

In Paul solving the equation, in the second step ${\mathrm{log}}_{3}x$ is directly replaced by ${3}^{x}$ which is not possible.

And the Scott’s solution is correct.

Hence, Scott is correct.

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