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Q32.

Expert-verified

Algebra 2

Found in: Page 424

Book edition Middle English Edition

Author(s) Carter

Pages 804 pages

ISBN 9780079039903

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Short Answer

Use the equation $x = 3 y^{2} + 4 y + 1$ to find the y-intercept.

The y-intercept of the equation $x = 3 y^{2} + 4 y + 1$ is $(0, - \frac{1}{3}) and (0, - 1)$ .

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Write down the given information.

The given equation is $x = 3 y^{2} + 4 y + 1$ .

Step 2. Calculation.

The y-intercept of the equation $x = 3 y^{2} + 4 y + 1$ can be obtained by plugging $x = 0$ in $x = 3 y^{2} + 4 y + 1$ . Therefore,

$\begin{matrix} x = 3 y^{2} + 4 y + 1 (Given) \\ (0) = 3 y^{2} + 4 y + 1.... (Plugging x = 0) \\ 3 y^{2} + 4 y + 1 = 0 \\ (3 y + 1) (y + 1) = 0 \\ 3 y + 1 = 0 or y + 1 = 0 \\ y = - \frac{1}{3} or y = - 1 \end{matrix}$

Step 3. Conclusion.

The y-intercept of the equation $x = 3 y^{2} + 4 y + 1$ is $(0, - \frac{1}{3}) and (0, - 1)$ .

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