Book edition Student Edition

Author(s) Carter, Cuevas, Day, Holiday, Luchin

Pages 801 pages

ISBN 9780078884801

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Short Answer

Evaluate each expression.
$C (10, 4)$

210

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Combination formula.

The number of combinations of $n$ objects taken $r$ at a time is the quotient of $n!$ and $(n - r)! r!$ , that is, $C (n, r) = \frac{n!}{(n - r)! r!}$ .

Step 2. Substitution.

Substitute 10 for $n$ and 4 for $r$ into combination formula.

$C (10, 4) = \frac{10!}{(10 - 4)! 4!}$

Step 3. Simplify.

Simplify the above obtained expression.

$\begin{array}{l} C (6, 3) = \frac{10!}{6! 4!} \\ = \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 \cdot 4 \cdot 3 \cdot 2 \cdot 1} \\ = 210 \end{array}$

The solution of given expression is 210.

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Algebra 1

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Short Answer

Evaluate each expression.
$C (10, 4)$

Step by Step Solution

Step 1. Combination formula.

Step 2. Substitution.

Step 3. Simplify.

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Algebra 1

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Short Answer

Evaluate each expression.C(10,4)

Step by Step Solution

Step 1. Combination formula.

Step 2. Substitution.

Step 3. Simplify.

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