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Q47.

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Found in: Page 659

### Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801

# Determine whether each set of measures can be the lengths of the sides of a right triangle.10, 12, 15

The given set of measures is not the lengths of the sides of a right triangle.

See the step by step solution

## Step 1. Given.

The length of the triangle is 10, 12, 15

## Step 2. Determine how to identify whether the given measures are the sides of the right triangle, acute triangle, an obtuse triangle.

If c, is the longest side of the triangle, a and b are the other two sides of the triangle then:

(i) If ${c}^{2}<{a}^{2}+{b}^{2}$, then the triangle is acute.

(ii) If ${c}^{2}={a}^{2}+{b}^{2}$, then the triangle is a right triangle.

(iii) If ${c}^{2}>{a}^{2}+{b}^{2}$, then the triangle is obtuse.

## Step 3. Determine whether the given set of measures can be the lengths of the sides of a right triangle.

The triangle is having sides of measures 10, 12, and 15.

The longest side of the triangle is 15.

Therefore, the value c is 15.

Therefore, the values of a and b are 10 and 12 respectively.

Now, it can be obtained that:

$\begin{array}{c}{a}^{2}={10}^{2}=100\\ {b}^{2}={12}^{2}=144\\ {c}^{2}={15}^{2}=225\\ {a}^{2}+{b}^{2}=100+144=244\end{array}$

It can be noticed that:

$\begin{array}{c}{a}^{2}+{b}^{2}=244\\ {a}^{2}+{b}^{2}\ne {c}^{2}\end{array}$

As, ${c}^{2}\ne {a}^{2}+{b}^{2}$, therefore, the triangle is not a right triangle.

Therefore, the given set of measures is not the lengths of the sides of a right triangle.