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Q5.

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Algebra 1
Found in: Page 466
Algebra 1

Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801

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Short Answer

Read each question. Then fill in the correct answer on the answer document provided by your teacher or on a sheet of paper.

Subtract the polynomials below.

7a2+6a24a3+3a2+5

  1. 4a3+4a2+6a7
  2. 11a2+3a7
  3. 4a3+10a2+6a+3
  4. 4a3+7a33a

The result obtained after the subtraction of the given polynomials is 4a3+4a2+6a7. Therefore, the option A is correct.

See the step by step solution

Step by Step Solution

Step 1. Define the additive inverse.

The additive inverse of a number ‘a’ is -a as a+a=0.

Step 2. Find the result obtained after the subtraction of the given polynomials.

The difference of the polynomials 7a2+6a2 and 4a3+3a2+5 can be find out by adding the polynomial 7a2+6a2 and additive inverse of the polynomial 4a3+3a2+5.

The additive inverse of the polynomial 4a3+3a2+5 is:

role="math" localid="1647689278588" 4a33a25

Therefore, it can be noticed that:

role="math" localid="1647689455168" 7a2+6a24a3+3a2+5=7a2+6a2+4a33a25 =7a2+6a2+4a33a25 =4a3+7a23a2+6a25 =4a3+4a2+6a7

Therefore, the result obtained after the subtraction of the given polynomials is 4a3+4a2+6a7. Therefore, the option A is correct.

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