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Q3B.

Expert-verifiedFound in: Page 283

Book edition
Student Edition

Author(s)
Carter, Cuevas, Day, Holiday, Luchin

Pages
801 pages

ISBN
9780078884801

**Solve each inequality. Then graph the solution set on a number line.**

**$\mathbf{5}\mathit{h}\mathbf{\le}\mathbf{12}\mathbf{+}\mathbf{4}\mathit{h}$**

The required solution set is represented by $\left\{h|h\le 12\right\}$** and the required graph is,**

Isolate *h* on any side of the provided inequality.

$\begin{array}{c}5h-4h\le 12+4h-4h\\ h\le 12\end{array}$

Make the conversion of obtained inequality to the notation named as set builder notation.

$\left\{h|h\le 12\right\}$

The graphical representation of the obtained solution set will consist of the number less than or equal to 12 so there will be a closed circle on 12.

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