Suggested languages for you:

Americas

Europe

Q3B.

Expert-verified
Found in: Page 283

Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801

Solve each inequality. Then graph the solution set on a number line.$\mathbf{5}\mathbit{h}\mathbf{\le }\mathbf{12}\mathbf{+}\mathbf{4}\mathbit{h}$

The required solution set is represented by $\left\{h|h\le 12\right\}$ and the required graph is,

See the step by step solution

Step 1. Determine the solution associated with the provided inequality.

Isolate h on any side of the provided inequality.

$\begin{array}{c}5h-4h\le 12+4h-4h\\ h\le 12\end{array}$

Step 2. Take the help of obtained inequality to write the solution set.

Make the conversion of obtained inequality to the notation named as set builder notation.

$\left\{h|h\le 12\right\}$

Step 3. Represent the obtained solution set in graphical form.

The graphical representation of the obtained solution set will consist of the number less than or equal to 12 so there will be a closed circle on 12.