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Q20.

Expert-verifiedFound in: Page 151

Book edition
Student Edition

Author(s)
Carter, Cuevas, Day, Holiday, Luchin

Pages
801 pages

ISBN
9780078884801

**Evaluate $\frac{a-b}{c-d}$ for each set of values.**

$a=-3,b=0,c=3,d=-1$

The value of expression is $-\frac{3}{4}$.

- To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
- To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
- To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
- To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition/ Subtraction:

- Two numbers with similar sign always get added and the resulting number will carry the similar sign.
- Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

- The product/quotient of two similar sign numbers is always positive.
- The product/quotient of two numbers with opposite signs is always negative.

In order to calculate $\frac{a-b}{c-d}$, substitute $-3$ for *a*, 0 for *b*, 3 for *c* and $-1$ for *d*.

$\frac{a-b}{c-d}=\frac{-3-0}{3-\left(-1\right)}$

Evaluate the expression in numerator and denominator.

$\begin{array}{c}\frac{a-b}{c-d}=\frac{-3-0}{3-\left(-1\right)}\\ =\frac{-3}{3+1}\\ =-\frac{3}{4}\end{array}$

Thus, the solution of the expression is $-\frac{3}{4}$.

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