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Q6.
Expert-verifiedWrite an equation of the line with the given conditions.
$\left(2,5\right)$; slope 3.
The equation of the straight line for the given condition is $\mathit{y}\mathbf{=}\mathbf{3}\mathit{x}\mathbf{-}\mathbf{1}$.
The standard form of slope and intercept form of the straight line is $y=mx+c$.
Here, $m$ is the slope of the straight line and $c$ is the $y$-intercept of the equation.
The standard form of slope and point form of the straight line is $y-{y}_{1}=m\left(x-{x}_{1}\right)$.
Here $m$ is the slope of the straight line and is the point from which the straight line passes.
$\begin{array}{l}\left({x}_{1},{y}_{1}\right)=\left(2,5\right)\\ m=3\end{array}$
Substitute the above values in the equation $y-{y}_{1}=m\left(x-{x}_{1}\right)$
$y-{y}_{1}=m\left(x-{x}_{1}\right)\phantom{\rule{0ex}{0ex}}y-5=3\left(x-2\right)\phantom{\rule{0ex}{0ex}}y-5=3x-6\phantom{\rule{0ex}{0ex}}y-5+5=3x-6+5\phantom{\rule{0ex}{0ex}}y=3x-1$
The equation of the straight line is $y=3x-1$.
The table shows the number of sales made at an outerwear store during a sale. Write an equation of the regression line. Then estimate the daily sales on day 10 of the sale
Days Since Sale Began | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Daily Sales ($\$$) | 15 | 21 | 32 | 30 | 40 | 38 | 51 |
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