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Expert-verified Found in: Page 244 ### Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801 # Write an equation of the line with the given conditions.$\left(2,5\right)$; slope 3.

The equation of the straight line for the given condition is $\mathbit{y}\mathbf{=}\mathbf{3}\mathbit{x}\mathbf{-}\mathbf{1}$.

See the step by step solution

## Step 1. State the concept of a straight line.

The standard form of slope and intercept form of the straight line is $y=mx+c$.

Here, $m$ is the slope of the straight line and $c$ is the $y$-intercept of the equation.

## Step 2. State the equation of a line slope-point form.

The standard form of slope and point form of the straight line is $y-{y}_{1}=m\left(x-{x}_{1}\right)$.

Here $m$ is the slope of the straight line and is the point from which the straight line passes.

$\begin{array}{l}\left({x}_{1},{y}_{1}\right)=\left(2,5\right)\\ m=3\end{array}$

## Step 3. Substitute the values to get the required equation.

Substitute the above values in the equation $y-{y}_{1}=m\left(x-{x}_{1}\right)$

$y-{y}_{1}=m\left(x-{x}_{1}\right)\phantom{\rule{0ex}{0ex}}y-5=3\left(x-2\right)\phantom{\rule{0ex}{0ex}}y-5=3x-6\phantom{\rule{0ex}{0ex}}y-5+5=3x-6+5\phantom{\rule{0ex}{0ex}}y=3x-1$

The equation of the straight line is $y=3x-1$. ### Want to see more solutions like these? 