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Q11.

Expert-verified

Algebra 1

Found in: Page 244

Book edition Student Edition

Author(s) Carter, Cuevas, Day, Holiday, Luchin

Pages 801 pages

ISBN 9780078884801

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Short Answer

Write an equation of the line that passes through the point $(0, 0)$ and has a slope $- 4$ .
A. $y = x - 4$
B. $y = x + 4$
C. $y = - 4 x$
D. $y = 4 - x$

The equation of the straight line for the given condition is $y = - 4 x$ . Option (C) is correct.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. State the concept of a straight line.

The standard form of slope and intercept form of the straight line is $y = m x + c$ .

Here, $m$ is the slope of the straight line and $c$ is the $y$ -intercept of the equation.

Step 2. State the equation of a line slope-point form.

The standard form of slope and point form of the straight line is $y - y_{1} = m (x - x_{1})$

Here $m$ is the slope of the straight line and is the point from which the straight line passes.

$(x_{1}, y_{1}) = (0, 0) m = - 4$

Step 3. Substitute the values to get the required equation.

Substitute the above values in the equation $y - y_{1} = m (x - x_{1})$

$y - y_{1} = m (x - x_{1}) y - 0 = - 4 (x - 0) y = - 4 x$

The equation of the straight line is $y = - 4 x$ . Option (C) is correct.

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