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Expert-verified Found in: Page 244 ### Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801 # Write an equation of the line that passes through the point $\left(0,0\right)$ and has a slope $-4$.A. $y=x-4$B. $y=x+4$C. $y=-4x$D. $y=4-x$

The equation of the straight line for the given condition is $y=-4x$. Option (C) is correct.

See the step by step solution

## Step 1. State the concept of a straight line.

The standard form of slope and intercept form of the straight line is $y=mx+c$.

Here, $m$ is the slope of the straight line and $c$ is the $y$-intercept of the equation.

## Step 2. State the equation of a line slope-point form.

The standard form of slope and point form of the straight line is $y-{y}_{1}=m\left(x-{x}_{1}\right)$

Here $m$ is the slope of the straight line and is the point from which the straight line passes.

$\left({x}_{1},{y}_{1}\right)=\left(0,0\right)\phantom{\rule{0ex}{0ex}}m=-4$

## Step 3. Substitute the values to get the required equation.

Substitute the above values in the equation $y-{y}_{1}=m\left(x-{x}_{1}\right)$

$y-{y}_{1}=m\left(x-{x}_{1}\right)\phantom{\rule{0ex}{0ex}}y-0=-4\left(x-0\right)\phantom{\rule{0ex}{0ex}}y=-4x$

The equation of the straight line is $y=-4x$. Option (C) is correct. ### Want to see more solutions like these? 