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Algebra 1
Found in: Page 492
Algebra 1

Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801

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Short Answer

Solve each equation. Check your solutions.


The solution of x25x=14 is role="math" localid="1647953707701" x=7,2.

See the step by step solution

Step by Step Solution

Step 1. Subtract.

Subtract from both sides of the given equation.

x25x14=1414 =0

Step 2. Factor by using GCF.

Factor by using GCF to get the form xy=0.


Step 3. Write zero product property.

For any real numbers x and y, if xy=0 then x=0,y=0 or both x and y equal to zero.

Step 4. Apply zero product property.

Apply zero product property to the given equation, x7x+2=0.

localid="1647954254435" x7=0 or x+2=0 x=7 x=2

Therefore, the roots are 7 and -2.

Step 5. Check the obtained solution.

To check whether the obtained solution is correct or not, substitute 7 for x and -2 for x in the given equation and simplify.

role="math" localid="1647954142827" 7257=?14 4935=?14 14=14LHS=RHS

2252=?14 4+10=?14 14=14LHS=RHS

Therefore, the obtained solution is correct.

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