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Q15.

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Algebra 1
Found in: Page 469
Algebra 1

Algebra 1

Book edition Student Edition
Author(s) Carter, Cuevas, Day, Holiday, Luchin
Pages 801 pages
ISBN 9780078884801

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Short Answer

Find each product.

3x2y2

9x212xy+4y2

See the step by step solution

Step by Step Solution

Step 1. Write a pattern of square of a difference.

The square of xy is the square of x minus twice the product of x and y plus square of y, that is,

width="158" height="48" role="math" style="max-width: none; vertical-align: -25px;" localid="1647752100488" xy2=xyxy =x22xy+y2

Step 2. Apply pattern of square of difference.

Apply the pattern of square of difference to the given expression.

3x223x2y+2y2

Step 3. Simplify.

Simplify the above obtained expression.

32x2232xy+22y2=9x212xy+4y2

Therefore, the product of 3x2y2 is 9x212xy+4y2.

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