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Problem 398

Consider the infinite trigonometric series $\left(a_{0} / 2\right)+{ }^{\infty} \Sigma_{n=1}\left(a_{n} \cos n x+b_{n} \sin n x\right)$ and assume that it converges uniformly for all \(\mathrm{x} \in(-\pi, \pi)\). It can then be considered as a function \(f\) of \(x\) with period \(2 \pi\), i.e. $\mathrm{f}(\mathrm{x})=\left(\mathrm{a}_{0} / 2\right)+{ }^{\infty} \sum_{\mathrm{n}=1} \mathrm{a}_{\mathrm{n}} \cos \mathrm{n} \mathrm{x}+\mathrm{b}_{\mathrm{n}} \sin \mathrm{n} \mathrm{x}$ Determine the values of \(a_{n}, b_{n}\) in terms of \(f(x)\)

Short Answer

Expert verified
In summary, the values of \(a_n\) and \(b_n\) in terms of \(f(x)\) can be determined using the following formulas: \(a_0 = \frac{1}{2\pi}\int_{-\pi}^{\pi} f(x) dx\) \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \cos(nx) dx\) \(b_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \sin(nx) dx\) These expressions can be used to find the Fourier series coefficients for any given periodic function \(f(x)\) with period \(2\pi\).
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Step 1: Identify Fourier series coefficients formula

First of all, let's note down the Fourier series coefficients formula for \(a_n\) and \(b_n\): \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \cos(nx) dx\) \(b_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \sin(nx) dx\) This is what we'll use to find the values of \(a_n\) and \(b_n\) for the given function \(f(x)\).

Step 2: Compute the coefficient a_0

We need to compute \(a_0\) separately because the formula for it is slightly different. The formula for \(a_0\) is: \(a_0 = \frac{1}{2\pi}\int_{-\pi}^{\pi} f(x) dx\) Now, we have the formula for \(a_0\). Let's move forward and find the values of \(a_n\) and \(b_n\) in terms of \(f(x)\).

Step 3: Apply the formulas for a_n and b_n

Using the formulas from step 1, let's find the general expressions for coefficients \(a_n\) and \(b_n\). It's important to notice that we are not computing a specific value, but we are looking for expressions in terms of \(f(x)\): \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \cos(nx) dx\) \(b_n = \frac{1}{\pi}\int_{-\pi}^{\pi} f(x) \sin(nx) dx\) We have obtained expressions for \(a_n\) and \(b_n\) in terms of \(f(x)\). With these expressions in place, you can substitute any given function \(f(x)\) to determine its Fourier series coefficients \(a_n\) and \(b_n\).

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